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-2a^2-11a-10=0
a = -2; b = -11; c = -10;
Δ = b2-4ac
Δ = -112-4·(-2)·(-10)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{41}}{2*-2}=\frac{11-\sqrt{41}}{-4} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{41}}{2*-2}=\frac{11+\sqrt{41}}{-4} $
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